I could be wrong, but my guess is he wants this first pass (I suppose because that's what I'd want)...

The only problem with twice is...it doesn't address what happens if there is a third, fourth and fifth (and so on) references...

On Sun, 8 Jan 2012, Andy Stevens wrote:

On 6 Jan 2012 21:12, <greg.zol...@aviall.com> wrote:
Say I have a string in a file like this:

       require(["a","foo/b","foo/c"], function(){...})

What I want to do is replace all the "foo" with "bar" so the final product
looks like this:

       require(["a","bar/b","bar/c"], function(){...})

With replaceregexp the best I've been able to get was below using regexp
like "require\(\s*\[(.*)foo/([^\]]*)\]"

       require(["a","foo/b","bar/c"], function(){...})

(I can't just do a global replace on "foo" because I only want to do the
replacement in this "require" context.)

Any ideas?

Run your regexp over the file twice? Second pass will catch the foo that
was left over the first time.

Andy.


Scot P. Floess             RHCT  (Certificate Number 605010084735240)
Chief Architect FlossWare  http://sourceforge.net/projects/flossware
                           http://flossware.sourceforge.net
                           https://github.com/organizations/FlossWare

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