Re: Re: probability of node receiving (not be responsible for) the request

2010/12/6 魏金仙 > thank you. > but I mean the probability of a node to receive the request not process it > eventually . I see. That depends on how the client-side load balancing is written. -Brandon

Re: probability of node receiving (not be responsible for) the request

2010/12/5 魏金仙 > If a particular client send 5 requests to a 6-node cluster, then the > probability of each node receiving(not be responsible for) the first request > is 1/6. Assuming RF=1 and RandomPartitioner. > Assume that node1 received the 1st request, will node1 receive the 2nd > reque