John,
What is R?
-Original Message-
From: ext John Meagher [mailto:john.meag...@gmail.com]
Sent: Wednesday, August 08, 2012 4:34 PM
To: user@hive.apache.org
Subject: Re: Converting rows into dynamic colums in Hive
I don't think having dynamic columns is possible in Hive. I've always ou
Actually as the custom UDF "yesterday()" mentioned below is NOT marked with the
annotation @UDFType(deterministic = false), partition pruning should work in
practice. The PartitionPruner has a logic around this annotation to check if a
generic UDF is deterministic or not and would skip partitio
The default seems to be 128. Can it be increased? I haven't found a
configuration parameter for that yet.
Keith Wiley kwi...@keithwiley.com keithwiley.commusic.keithwiley.com
"Luminous beings are we, n
I don't think having dynamic columns is possible in Hive. I've always
output from Hive a structure like your query output and used R to
convert it into a dynamic column structure.
On Wed, Aug 8, 2012 at 3:56 PM, wrote:
> Thanks Ashish, that gives an idea.
>
> But I am not sure about the outer
Thanks Ashish, that gives an idea.
But I am not sure about the outer select loop, I have to know all the values in
Beta column beforehand to do a max on each value.
Is there a better way?
Richin
From: ext Ashish Thusoo [mailto:athu...@qubole.com]
Sent: Tuesday, August 07, 2012 5:05 PM
To: user@h
Hi,
I'm trying to integrate Hive in our Cassandra-Hadoop stack, but I'm finding it
difficult to understand what's the right approach.
As far as I see, there are 2 jira issues open (one in Hive, on in Cassandra)
https://issues.apache.org/jira/browse/CASSANDRA-4131
https://issues.apache.org/jira/
I have a large amount of data JSON data that was generated using
periods in the key names, e.g., {"category.field": "value"}. I know
that's not the best way to do JSON but for better or worse, it's the
data I have to deal with.
I have tried using get_json_object, but I am concerned that it's JSON
Thanks Bejoy. What if those values a,b are not static and are housed in a
table. Much like a type 2 dimension. Is the current solution still to put it in
the where clause?
Thanks,
Ranjith
From: Bejoy Ks [mailto:bejoy...@yahoo.com]
Sent: Wednesday, August 08, 2012 06:55 AM
To: user@hive.apache.o
Hi Ranjith
BETWEEN a and b, you can implement as >=a , <=b . Since that is not equality
you cannot use that in ON clause you need to move it to WHERE condition in your
query.
Regards,
Bejoy KS
From: "Raghunath, Ranjith"
To: "'user@hive.apache.org'"
Sent
Hi Raihan
UDFs are evaluated at run time when the query is executed. But it is hive
parser during query parse time decides the boundary of data to be used for the
query, ie data from which all partitions has to be processed.Because of this
the entire table will be scanned for your query.
Re
Any comments/information on the below issue is highly appreciable J
From: Balaraman, Anand [mailto:anand_balara...@syntelinc.com]
Sent: 06 August 2012 18:25
To: user@hive.apache.org
Subject: Special character replaced by '?'
Hi
I am facing an issue while viewing special characters (suc
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