RE: Using an UDF in the WHERE (IN) clause

2014-03-11 Thread java8964
What version of hive you are using? It is good to know that if it works in newer version. Yong Date: Tue, 11 Mar 2014 08:33:06 +0100 Subject: Re: Using an UDF in the WHERE (IN) clause From: petter.von.dolw...@gmail.com To: user@hive.apache.org Hi Young, I must argue that the partition pruning

Re: Using an UDF in the WHERE (IN) clause

2014-03-11 Thread Petter von Dolwitz (Hem)
Hi Navis, I suspected that the parser only accepted an expression like (value1, value2, value3...) as input. I guess one solution as you say would be to add an array as an allowed argument to IN. I do not know if other SQL dialects allow this. Another way would be to introduce a new type of UDF th

Re: Using an UDF in the WHERE (IN) clause

2014-03-11 Thread Navis류승우
Then you should use BETWEEN, not IN. BETWEEN can be used for PPD, afaik. 2014-03-11 16:33 GMT+09:00 Petter von Dolwitz (Hem) : > Hi Young, > > I must argue that the partition pruning do actually work if I don't use the > IN clause. What I wanted to achieve in my original query was to specify a > r

Re: Using an UDF in the WHERE (IN) clause

2014-03-11 Thread Petter von Dolwitz (Hem)
Hi Young, I must argue that the partition pruning do actually work if I don't use the IN clause. What I wanted to achieve in my original query was to specify a range of partitions in a simple way. The same query can be expressed as SELECT * FROM mytable WHERE partitionCol >= UDF("2014-03-10") and

Re: Using an UDF in the WHERE (IN) clause

2014-03-10 Thread Navis류승우
(KW_IN expressions) -> ^(TOK_FUNCTION KW_IN $precedenceEqualExpression expressions) expressions : LPAREN expression (COMMA expression)* RPAREN -> expression* ; You should have arguments of IN wrapped by parentheses. But It seemed not possible to use array returning expression i

RE: Using an UDF in the WHERE (IN) clause

2014-03-10 Thread java8964
I don't know from syntax point of view, if Hive will allow to do "columnA IN UDF(columnB)". What I do know that even let's say above work, it won't do the partition pruning. The partition pruning in Hive is strict static, any dynamic values provided to partition column won't enable partition pru