Now that we've figured all that out, and determined that it's not built-in to
Cypher yet... What is the best practice for doing this with the available
tools?
I mean effectively what I'm looking for is the heaviest branch on a tree
right?
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g like this:
>
> RETURN SUM(MAP(x in NODES(path) : x.votes))
>
I should read more carefully before I start typing. :-) Yes. This makes
the most sense to me.
On Tue, Oct 25, 2011 at 12:02 PM, n_aschbacher <nathan@>wrote:
> Hi,
>
> You're correct in one sens
Hi,
You're correct in one sense. If I remove the path, or other columns, from
the RETURN statement then I can get a single SUM value back for all the
properties in the entire tree below my starting node.
My problem is that I want to return multiple rows, a row for each path
through the graph, wi
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