Hi,
I'm a little bit confused about Mahout's clustering algorithms. I like to
clustering data with id column. How can I do that?
For example, I like to run K-Means clustering on the Iris data set (
http://archive.ics.uci.edu/ml/datasets/Iris) where I've got four numerical
columns. I generated an i
The NamedVector class adds a string to any vector, forwarding all
methods to the wrapped vector. You can cluster these, and then pull
the strings. The clustering algorithm operates on the wrapped vector.
Lance
On Sun, Jul 10, 2011 at 4:18 PM, Gabor Makrai wrote:
> Hi,
>
> I'm a little bit confus
Thank you very much! NamedVector has to solve my problem!
Anyway, I'm always wondering the answer speed in the Hadoop lists!
Thank you,
Gabor
On Mon, Jul 11, 2011 at 3:51 AM, Lance Norskog wrote:
> The NamedVector class adds a string to any vector, forwarding all
> methods to the wrapped vector
I'm finding it hard to maintain these labels across vector and matrix
factorizations & direct operations.
On Mon, Jul 11, 2011 at 1:10 AM, Gabor Makrai wrote:
> Thank you very much! NamedVector has to solve my problem!
> Anyway, I'm always wondering the answer speed in the Hadoop lists!
>
> Thank
I mean, walking through the algorithms and tracking what vector name
becomes what matrix row/column label.
On Mon, Jul 11, 2011 at 8:58 PM, Lance Norskog wrote:
> I'm finding it hard to maintain these labels across vector and matrix
> factorizations & direct operations.
>
> On Mon, Jul 11, 2011 a
Can you give specific examples? The process should be relatively
straightforward and the implication that rows have row labels that are
defined by the left operand of a product and columns have column labels that
are defined by the right operand should be sufficient. Sums should have the
same row
My algorithm was wrong anyway, and was making things harder for myself
than I needed.
On Mon, Jul 11, 2011 at 9:36 PM, Ted Dunning wrote:
> Can you give specific examples? The process should be relatively
> straightforward and the implication that rows have row labels that are
> defined by the l
