Coveney,
Thanks for the reply
Got the answer using nested foreach.
a = load 'data' using PigStorage(',');
b = foreach a {
c = substring(col1,0,4);
generate
332 as x,
c;
}
Sent from my iPhone
On May 7, 2013, at 4:33 AM, Jonathan Coveney jcove...@gmail.com wrote:
cdh-user to bcc
Your
Hi,
I have data of format
id1,id2, value
1 , abc, 2993
1, dhu, 9284
1,dus,2389
2, acs,29392
and so on
For each id1, I want to find the maximum value and then divide value by
max_value
so in example above:
1,abc, 2993/9284
1,dhu ,9284/9284
1,dus, 2389/9284
2,acs, 29392/max_value_for_this id
values = LOAD 'my_path' AS (id1:int, id2:chararray, value:int);
overall = FOREACH (GROUP values BY id1) GENERATE group AS id1,
value/MAX(value) as div_max;
Russell Jurney http://datasyndrome.com
On Apr 27, 2013, at 2:32 AM, jamal sasha jamalsha...@gmail.com wrote:
Hi,
I have data of format
Hi,
I have a table in format:
Id: int, amount: float, true_date: chararray, time:chararray,
state:chararray
Fortunately, there are only two states in my db.
So if I have a state as “CA” then add +1 to datetime
If state is “MA”, then add +5 to datetime
And then save the results.
Also a
Hi Jamal,
you can write a UDF convert time between different time zones with
following utilities,
java.text.DateFormat;
java.text.SimpleDateFormat;
java.util.Date;
java.util.TimeZone;
Thanks,
TianYi
On Thu, Oct 4, 2012 at 12:53 AM, jamal sasha jamalsha...@gmail.com wrote:
Hi,
I have a
0) convert dates to ISO format via CustomFormatToISO
1) convert dates to unix time longs via ISOToUnix
2) use foreach/generate with ternary operator to add/subtract hours
based on the value of the other field
3) convert dates back to ISO format with UnixToISO
Call it a day.
Russell Jurney
