Are you running this code in web container? If so, which? Tomcat,
Jetty, JBoss?
If you are just running as a standalone Java app, you can just use
"SimpleRegistry", which is basically a Map.
CamelContext context = new DefaultCamelContext(new SimpleRegistry());
Registry registry
I meant that I in the RouteBuilder::configure have;
JndiRegistry registry = (JndiRegistry) getContext().getRegistry(); // DO NOT
WORK!
---
Thanks for the suggestion. The code
PropertyPlaceholderDelegateRegistry registry =
(PropertyPlaceholderDelegateRegistry) getContext().getRegistry()
It may, or may not be wrapped in PropertyPlaceholderDelegateRegistry,
in that case, I would try this:
Registry registry = context.getRegistry();
if (registry instanceof PropertyPlaceholderDelegateRegistry)
registry =
((PropertyPlaceholderDelegateRegistry)registry).getRe
On Mon, Mar 18, 2013 at 2:02 PM, Gert Villemos wrote:
> Hmmm... tried that but doesnt work.
>
> getContext() returns a
> org.apache.camel.impl.PropertyPlaceholderDelegateRegistry object. Which cant
> be cast to JndiRegistry.
>
> My setup is the following; In a Spring based route I have bean A. Bea
Hmmm... tried that but doesnt work.
getContext() returns a
org.apache.camel.impl.PropertyPlaceholderDelegateRegistry object. Which cant
be cast to JndiRegistry.
My setup is the following; In a Spring based route I have bean A. Bean As
@Handler will create an instance of bean B, which is a RouteBu
On Mon, Mar 18, 2013 at 12:16 PM, Gert Villemos wrote:
> How can I in the 'configure' method of a RouteBuilder add beans to the
> registry?
>
> Im in a RouteBuilder creating a route using Netty. The Netty URL reference
> encoder/decoder beans. I need to create and insert these beans in the
> regis
