exchange.in returns an Object, so there is no getHeader method
available on that.
There is an exchange.header but like I said it seems to return some
DSL construct that I can't figure out how to get the value out of.
On 1 November 2012 09:52, Willem jiang wrote:
>
> in.getHeader("header-name")
in.getHeader("header-name") should work for you.
--
Willem Jiang
Red Hat, Inc.
FuseSource is now part of Red Hat
Web: http://www.fusesource.com | http://www.redhat.com
Blog: http://willemjiang.blogspot.com (http://willemjiang.blogspot.com/)
(English)
http://jnn.javaeye.com (http://
If you can access the exchange directly, you can use exchange.in("header-key")
to access the in message header.
--
Willem Jiang
Red Hat, Inc.
FuseSource is now part of Red Hat
Web: http://www.fusesource.com | http://www.redhat.com
Blog: http://willemjiang.blogspot.com (http://willemjiang.blogs
Hi all,
How can I get the value of a header from an exchange using the Scala
DSL. Maybe I'm going mad but
in.header("header-name")
gives me a variable of type HeaderExpression or HeaderLanguage (can't
remember which) and I can't seem to get the "value" from that ?
