My guess would be that we're pushing the PythonContext._callSplatSite outside
of the sweet spot in DLR site caches.
You could check this by putting a breakpoint in PythonContext.Call(object,
params object[]). Then look and see if _callSplatSite._rules is an instance of
EmptyRuleSet with _suppo
Michael,
Thank you for your help! It finally works. Now there is lots of other things
left but this has really helped a lot.
2008/12/16 Michael Foord
> Kristian Jaksch wrote:
>
>>
>> Michael,
>>
>> What do you mean exec the import * inside the context to poulate it?
>> Something like:
>>
>> *
Kristian Jaksch wrote:
Michael,
What do you mean exec the import * inside the context to poulate it?
Something like:
*context['Mapack'] = exec "from Mapack import *" #Doesn't work
*Hmmm... think I'm getting tired.
exec doesn't return anything.
Try:
*exec "from Mapack import *" in cont
We see a very strange side effect of running the follwing code on the
performance of recalculations in Resolver One.
def Dumbcorator(fn):
def _inner(self, *args):
return fn(self, *args)
return _inner
class Locker(object):
@property
@Dumbcorator
def thing(self):
We see a very strange side effect of running the follwing code on the
performance of recalculations in Resolver One.
def Dumbcorator(fn):
def _inner(self, *args):
return fn(self, *args)
return _inner
class Locker(object):
@property
@Dumbcorator
def thing(self):
Orestis,
passing the 'context' to 'eval' seems like the right thing to do. I tried
your solution, see below:
*
clr.AddReference("Mapack, Version=1.0.0.0, Culture=neutral,
PublicKeyToken=null")
from Mapack import *** #A library that contain classes for working with
algebra etc.*
.
.
.
*contex
Michael Foord wrote:
Kristian Jaksch wrote:
*
def inputBox_KeyDown(s, e):
key = e.Key.value__
result = root.inputBox.Text
if key == 3: #If 'Enter' key is pressed
try:
try:
root.message.Text = eval(result)
except SyntaxError:
exec result in
you have to pass the context to eval as well:
eval(result, context)
make sure that the context doesn't change between calls to eval and
exec. It should be a property on your form, really, but it doesn't seem
so. Just make sure that you don't re-create the context every time.
If you don't wan
Kristian Jaksch wrote:
Ok, did you mean something like below?:
*
clr.AddReference("Mapack, Version=1.0.0.0, Culture=neutral,
PublicKeyToken=null")
from Mapack import *** #A library that contain classes for working
with algebra etc.*
*context = {}
context['m'] = Matrix(5,5)#creating
Ok, did you mean something like below?:
*
clr.AddReference("Mapack, Version=1.0.0.0, Culture=neutral,
PublicKeyToken=null")
from Mapack import *** #A library that contain classes for working with
algebra etc.*
*context = {}
context['m'] = Matrix(5,5)#creating a 5 rows, 5 columns matrix o
xkrja wrote:
Thanks!
I'm using Ironpython with Silverlight so I can't get access to Windows.Forms
Ah - in which case it probably lives in System.Windows.Input
Please bear with me :-) New stuff's showing up all the time. The solution
you proposed worked but there must be something I don't g
Thanks!
I'm using Ironpython with Silverlight so I can't get access to Windows.Forms
Please bear with me :-) New stuff's showing up all the time. The solution
you proposed worked but there must be something I don't get with the scope.
Please look at my snippet below:
import clr, sys
clr.AddRef
Oh - and Windows Forms has a Keys enumeration so that you don't have to
rely on the underlying value of the event key property.
from System.Windows.Forms import Keys
if e.Key == Keys.Enter:
(or something like that - check out the MSDN documentation for the
enumeration.)
Michael Foord
Mich
context = {}
def inputBox_KeyDown(s, e):
root.message.Text = ''
key = e.Key.value__
result = root.inputBox.Text
if key == 3: #If 'Enter' key is pressed
try:
try:
root.message.Text = eval(result)
except SyntaxError:
exec result in contex
Thanks for the reply.
Below is a snippet of what I've got:
def inputBox_KeyDown(s, e):
root.message.Text = ''
key = e.Key.value__
result = root.inputBox.Text
if key == 3: #If 'Enter' key is pressed
try:
root.message.Text = eval(result)
except:
xkrja wrote:
Thanks for the replies guys.
I tried the solution below and it works in some cases. But a strange thing
is (remember I'm a newbie) that if I first type, for example a=1 in the
"inputBox" and then hit enter, the debugger goes down to exec
root.inputBox.Text and nothing is reported so
Thanks for the replies guys.
I tried the solution below and it works in some cases. But a strange thing
is (remember I'm a newbie) that if I first type, for example a=1 in the
"inputBox" and then hit enter, the debugger goes down to exec
root.inputBox.Text and nothing is reported so I assume the
You would find the same thing in CPython. When you execute Program.py it
is run with the name '__main__' (the main program being executed). When
you import it, you import it with the name 'Program' which causes it to
be imported with a different name. I suggest you put your debug symbol
in a se
I use IronPython 2.0.
In Program.py I have:
print "hello"
DEBUGMODE=0
.
.
.
import LogMessage
In LogMessage.py I have
from Program import DEBUGMODE
When I run :
ipy Program.py
I observe that "hello" is printed twice: Once when Program.py is run and
next when a symbol from Program.py is imported
This is just a Python issue (not specific to IronPython).
exec is used for statement(s) and eval() for expressions. You might have to:
try:
eval(root.inputBox.Text)
except:
exec root.inputBox.Text
-Doug
- xkrja wrote:
>
> Thanks for the reply. This is what I have:
>
> def inputBox_
xkrja wrote:
Thanks for the reply. This is what I have:
def inputBox_KeyDown(s, e):
root.message.Text = ''
key = e.Key.value__
if key == 3:
result = eval(root.inputBox.Text)
root.message.Text = str(result)
eval() seems to work sometimes. For example if the text in th
Thanks for the reply. This is what I have:
def inputBox_KeyDown(s, e):
root.message.Text = ''
key = e.Key.value__
if key == 3:
result = eval(root.inputBox.Text)
root.message.Text = str(result)
eval() seems to work sometimes. For example if the text in the textbox is
1
I'm not sure about sockets. The only example I have found in the wild so
far is with files in PIL.
The python implementation seems to have socket.fileno() returning a file
descriptor which comes from 's socketpair function in the
standard C library (see socketmodule.c if you are interested)
2008/12/16 xkrja :
>
> Hi,
> I'm just starting out learning IronPython. How can I convert a string that
> someone writes in a textbox to a python expression or statement?? Compare it
> to the console input: If I write for example a=2 in the console it's not
> just a string I assume? It becomes an e
Hi,
I'm just starting out learning IronPython. How can I convert a string that
someone writes in a textbox to a python expression or statement?? Compare it
to the console input: If I write for example a=2 in the console it's not
just a string I assume? It becomes an expression in the python code o
Thanks a lot again.
> If you have only one version/culture, I believe you can just place
> the XML doc in the same directory as the DLL.
>
>
>>
>> It seems clear now, thank you.
>>
>> Reading DocBuilder.cs:GetXPathDocument(..) I assume that if I want
>> to let our users to be able to get IP c
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