[Pw_forum] LDA+U or GGA+U?

2012-03-12 Thread GAO Zhe
Dear QE developer and users: I just began to try LDA+U method in QE, by adding lda_plus_u = .true. and Hubbard_U(i) parameters to scf input file, where the U value was determined by following M.Cococcioni's thesis and Prof. Marzari's paper (PRL, 97, 103001). However, when I check other code

[Pw_forum] LDA+U or GGA+U?

2012-03-12 Thread Abdeslam HOUARI
Dear GAO Zhe; As told by Lorenzo Paulatto, I think that LDA+U is just a name and all the important thing is how to include the Hubbard "U" term. However, in may opinion, this still being true only for DFT (LDA or GGA) XC functional, and one should take care if the XC functional is a Hybrid-type

[Pw_forum] LDA+U or GGA+U?

2012-03-12 Thread Lorenzo Paulatto
On Mon, 12 Mar 2012 12:21:30 +0100, GAO Zhe wrote: > Therefore, I am wondering that, if I setted lda_plus_u = .true. and used > GGA pseudo-potential, may I say I am using GGA+U method? Yes, you may. The +U correction can be applied to any kind of functional. The "lda" in "lda+U" is just a