On Wednesday, March 20, 2013 23.43 CET, Serge Steer serge.st...@inria.fr
wrote:
If you know the approximate size of the footer in number of bytes (assume N
greater than it) you can try to set the pointer N bytes before the end of
file using the
u=mopen(myfile);
mseek(-N,u,'end')
Strange, at me houses my computer gives out always 0..
Has tested on the working computer 0.047.
Question I think I shall be closed to understand what a problem of a house.
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Hello, sometimes, when I try to load an eviroment, I got a message like
this:
loading initial environment
Warning : redefining function: %_sodload . Use
funcprot(0) to avoid this message
inside function: createMacro .
= (pos,V,R,calc_D_superp_dobcel(N, N2))
hello,
for signalanalysis I would like to use discrete Fourier transform (dft). To
see, how it works, I use the simple example below. Why is *XfA =
abs(Xf)*2/n* respectively why is XfA = abs(Xf) wrong?
clear; clc; xdel;
function y = f(x);
y = sin(x);
endfunction;
n = 200;
Hello everybody,
I'd like to set parameters of my scs_m structure for an Xcos Diagram (see
attached file) using command lines.
To be specific I'd like to set the following imulation parameters :
- final integration time
- max integration time interval
I want them to be equal to a dt that I
Le 21/03/2013 16:41, haasejos a écrit :
hello,
for signalanalysis I would like to use discrete Fourier transform (dft). To
see, how it works, I use the simple example below. Why is *XfA =
abs(Xf)*2/n* respectively why is XfA = abs(Xf) wrong?
Why do you say that XfA = abs(Xf) is wrong
Note
The people, I have checked up houses once again, a problem in that that if to
create test script in a file for example TicToc.sci and to start this file,
shows always 0.00, and if to copy the text to insert and to start in
a command window directly without start of a file. sci (or sce)
On 2013-03-21 17:13, Serge Steer wrote:
Le 21/03/2013 16:41, haasejos a écrit :
hello,
for signalanalysis I would like to use discrete Fourier transform
(dft). To
see, how it works, I use the simple example below. Why is *XfA =
abs(Xf)*2/n* respectively why is XfA =
good evening,
what I meant is, that XfA(2) should be 1. Because this value can be
understood as the amplitude of sin(x). But XfA(2) beeing calculated with
XfA=abs(Xf) (see example) returns 100. This is wrong, isn't it?
Josef
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Hi,
I think this is just a question of scaling. There is no correct scaling
for the FFT - just some different conventions. This is explained here
(http://www.mathworks.co.uk/matlabcentral/answers/15770-scaling-the-fft-and-
the-ifft).
The correct answer with Scilab would be exactly 100 (N/2) in
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