That's not at all atypical, and it's what you expect from a numerical
process to arrive at an eigenvector matrix. In the context of ones on
the main diagonal, 1e-16 is mostly zero.
On 2015-06-22 03:08, Carrico, Paul wrote:
Dear Tim,
Thanks for the enlightenment, but unfortunately I confess
Hi,
I don't think there is a problem (on my 5.5.2 version) :
function hm_display(m,n,l)
a = rand(m, n, l);
for i = 1:m
for j = 1:n
for k = 1:l
mprintf(value of index [%d, %d, %d] = %f \n, i, j, k,
a(i, j, k))
end
Dear all,
I stumbled across a strange behavior I don't understand correctly.
Please also refer to the simplified code extract below.
Apparently beta(x,y) refers to a built in SciLab function (beta function
(Euler integral of the first kind)). If I redefine the function by a simple
vector
Dear Tim,
Thanks for the enlightenment, but unfortunately I confess I don't know how to
proceed now;
I feel that I need to fix such issue; another example if needed (see screenshot
in attachment), the product herebellow should lead to the Identity matrix
Verif1 = u' * M * u
(vhere u is the
Hello Dominic,
Le 22/06/2015 11:31, DominicErnst a écrit :
.../...
Now, if I try to write-access a particular value in this now initialized
vector I get the Warning Warning: obsolete use of '=' instead of '=='..
It looks like a bug.
After the beta=zeros(1:10)'; overwriting assignment,
Hi Samuel
Thanks for your reply. That's what I thought, but as a beginner I'm always
careful saying 'This is a bug', as I am not always sure I got everything
right. Using Beta instead of beta is a good idea. Thanks a lot.
Best,
Dominic
-
--
Dominic Ernst
CNC-PLC Software Developer @
Let x=zeros(m,n,l)
if m==1, x is generated as 2 dimension matrix, not 3 dim hyper-matrix.
In that case the specification of elemnt like x(i,j,k) fails.
But the value of m is unknown in advance.
Is there any code which I can deal with such a case in general way?
I don't like such as if m==1 then …
