Re: [Scilab-users] Bode of discret time transfer function.

2017-03-01 Thread Pablo Fonovich
iado: sábado, 25 de febrero de 2017 06:57 p.m. Para: Users mailing list for Scilab Asunto: Re: [Scilab-users] Bode of discret time transfer function. Not sure what you're trying to achieve, but if you want a plot of the linear amplitude response on a linear frequency line, use Horner: H = syslin('d

Re: [Scilab-users] Bode of discret time transfer function.

2017-02-25 Thread Tim Wescott
Not sure what you're trying to achieve, but if you want a plot of the linear amplitude response on a linear frequency line, use Horner: H = syslin('d', (%z - 0.9) / (%z - 99)); th = %pi * (-1:0.01:1)'; clf; plot2d(th, abs(horner(H, exp(%i * th; xgrid(2) On Sat, 2017-02-25 at 18:17 +,

Re: [Scilab-users] Bode of discret time transfer function.

2017-02-25 Thread Tim Wescott
First, 'bode' is going to give you a Bode plot, and it's going to be insistent on giving it to you in log-log format -- so if you want a plot on a linear frequency axis from -pi to +pi, then you need to do it by hand. Second, 'bode' is pretty insistent about reporting things as per second -- if

Re: [Scilab-users] Bode of discret time transfer function.

2017-02-25 Thread Serge Steer
Le 25/02/2017 à 19:17, Pablo Fonovich a écrit : Hi: This is the first time i work with discrete time transfers functions and Scilab. I want to use bode() for plotting the magnitud and phase response of the system, however, i don't understand how to set the frequencies to normalized values

[Scilab-users] Bode of discret time transfer function.

2017-02-25 Thread Pablo Fonovich
Hi: This is the first time i work with discrete time transfers functions and Scilab. I want to use bode() for plotting the magnitud and phase response of the system, however, i don't understand how to set the frequencies to normalized values (-pi, pi). This is what i'm doing: s=poly(0,'s')