X = hilbert(data) computes the hilbert transform of data(:) not a N
dimensionnal Hilbert transform.
Please find attached a function which is intended to compute the N dimensionnal
Hilbert transform obtained applying
the 1D hilbert transform to all columns then to all rows,
This function e
So what would the syntax be for doing a column run Hilbert, and row run Hilbert?
It does sound like the suggesting would do what I think it is meant to.
X = hilbert(data) // does compute pretty fast!
At the moment I have used the netCDF code to read in GMT (net CDF)
data, which is a 601 x 601 ma
Any time you go from 1D to 2D you suddenly end up with more than one way
to do things, so I'm pretty sure that "how would one..." should really
be worded "how would YOU...", or perhaps "how would someone in this
field...".
It sounds like you want to keep things rectilinear, so it may be best to
ju
Hi Serge,
I am working with grid data, so looking for the 2D Hilbert, the
results I think should appear similar to doing a directional
derivative, where X highlights features with N-S trends and E-W for Y.
Lester
On 5 February 2016 at 12:24, Serge Steer wrote:
> Le 05/02/2016 10:56, Lester An
Le 05/02/2016 10:56, Lester Anderson a écrit :
Hello
A quick query. How would one define the Hilbert transform of a grid
for X and Y directions; looking for two solutions Hx and Hy (for the
real values).
Can you explain more precisely what you expect?
Do you want to apply Hilbert transform to
Hello
A quick query. How would one define the Hilbert transform of a grid
for X and Y directions; looking for two solutions Hx and Hy (for the
real values).
Thanks
Lester
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