Le 01/07/2016 11:17, Pierre Vuillemin a écrit :
>
> You can create another object, a matrix of bing int that stacks your
> bigint in a list, i.e.
Yes I've created another object but as an mlist as recommanded Samuel.
Thanks for your help,
Philippe
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Le 01/07/2016 11:33, Samuel Gougeon a écrit :
> Hello Philippe,
> You shall use a mlist() instead of a tlist.
> Have a look at https://help.scilab.org/docs/6.0.0/en_US/mlist.html
> mlist are array-oriented.
thanks Samuel, I will create mbigint as a mlist containing the cell of
bigint and a string
Hi Philippe,
You can create another object, a matrix of bing int that stacks your
bigint in a list, i.e.
x = tlist(["bigint","rep","signe"],[7654321;5678998;1234],1)
y = tlist(["bigint","rep","signe"],[3456789;5432112;9876],1)
X = tlist(["mbigint","entries"],list(x,y))
Then you can overload
Hi,
I have created a simple data structure to handle "big integers" . It is
based on scilab tlist and named "bigint" . I have overloaded basic
unary/binary operators for bigint (like +,*,-,/,^,==,<,>,... ) :
-->x=bigint('123456789987654321')
x =
123456789987654321
-->y=bigint('98765432
