abity
-Message d'origine-
De : users De la part de Izabela
Wójcik-Grzaba
Envoyé : mercredi 10 avril 2019 17:31
À : Users mailing list for Scilab
Objet : Re: [Scilab-users] Nested function definition
Ok, sorry. It's my mistake connected with using math terms not
properly.
Now I underst
Objet : Re: [Scilab-users] Nested function definition
Ok, sorry. It's my mistake connected with using math terms not properly.
Now I understand that nested function is more general term in Scilab help. The
help example is similar to mine and this is the whole misunderstanding.
I appre
Ok, sorry. It's my mistake connected with using math terms not properly.
Now I understand that nested function is more general term in Scilab
help. The help example is similar to mine and this is the whole
misunderstanding.
I appreciate your comprehensive explanation.
Now I am happy because the
Izabela,
I have not clearly understood why you are speaking about "nested
functions" in your example.
A nested function is a function that is /defined/ in another one.
About the example in the function help page:
It is right, but with Scilab 6, it looks a bit outdated to me.
Indeed, let's con
Izabela Wójcik-Grzaba
Sent: Wednesday, April 10, 2019 5:04 PM
To: Users mailing list for Scilab
Subject: Re: [Scilab-users] Nested function definition
Ok, so why nested function in help is so complicated:
//nested functions definition
function y=foo(x)
a=sin(x)
function y=sq(x), y=x^2
2019 3:01 PM
To: Users mailing list for Scilab
Subject: Re: [Scilab-users] Nested function definition
Thank you. Is there a way to use this formulation as an input function
to fsolve? I don't know how to do it.
In my another example I also had a nested function but I managed to
define it in
-Original Message-
From: users On Behalf Of Izabela Wójcik-Grzaba
Sent: Wednesday, April 10, 2019 3:01 PM
To: Users mailing list for Scilab
Subject: Re: [Scilab-users] Nested function definition
Thank you. Is there a way to use this formulation as an input function to
fsolve? I don't know how
Thank you. Is there a way to use this formulation as an input function
to fsolve? I don't know how to do it.
In my another example I also had a nested function but I managed to
define it in a form like in help page about function. It means that
everything was inside one function. This formulat
Hello,
Le 09/04/2019 à 20:17, Rafael Guerra a écrit :
globalmg h l L0;
The above line is useless no ?
mg= 0.1; h=0.1; l=0.1; L0=0.1;
function*e*=_eta_(*q*)
*e*= mg./(2**q*)
endfunction
function*z*=_zeta_(*q*)
*z*= asinh(mg.*h./(2**q*.*l.*sinh(_eta_(*q*+_eta_(*q*);
endfunction
fun
global mg h l L0;
mg = 0.1; h=0.1; l=0.1; L0=0.1;
function e=eta(q)
e= mg./(2*q)
endfunction
function z=zeta(q)
z= asinh(mg.*h./(2*q.*l.*sinh(eta(q+eta(q);
endfunction
function y=URQ(q, e, z)
y= mg.*L0./(q.*l)-sinh(2*e-z)-sinh(z)
endfunction
q=1;
y=URQ(q,eta(q),zeta(q))
Rgds,
R
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