Ulf, See the link below. I think you may need to explicitly add your Resources folder to the Project sources, since it is outside the src folder, and this is done with the project properties as shown in the link.
https://stackoverflow.com/questions/6845231/how-to-correctly-get-image-from-resources-folder-in-netbeans I wouldn't worry too much about using Ant. I still use it. Many still use it. Use what works for you. Thank You! Joe Huber Standard Refrigeration LLC From: Ulf Zibis <ulf.zi...@cosoco.de> Sent: Sunday, June 23, 2024 1:06 PM To: users@netbeans.apache.org Subject: Re: How to integrate a resource file into the final JAR You don't often get email from ulf.zi...@cosoco.de<mailto:ulf.zi...@cosoco.de>. Learn why this is important<https://aka.ms/LearnAboutSenderIdentification> Hi Stephen, thanks for your inspiration. I'm using an ANT project. I never managed how to go with Maven. So my file structure is: Project + src + Java ... + test + Java ... + resources + Palm8BitColors.pal + TestData + ... So you mean, that I should move the resource file into the src path. I was thinking, that there is a way to configure the NetBeans build properties, so that the file will be included into the JAR. But I have forgotten how to do. Using getResourceAsInputStream() is a good idea. Actually I need the file content in a byte array or ByteBuffer. -Ulf Am 23.06.24 um 19:20 schrieb Stephen G. Parry: Are you using a Java with Maven project? Assuming so, the process for what you are asking is a two step one: 1) Ensure the files you wish to access are located under the src/main/resources folder as shown here: https://i0.wp.com/www.dineshonjava.com/wp-content/uploads/2016/10/Maven-dirctory-structure.png?w=728&ssl=1 Doing this should ensure that the file is picked and included in the compiled jar file. 2) You will need to add to your code. What exactly you add will depend on whether you are opening the file from a static member or a proper member function and whether you really need an FileInputStream or just an InputStream. I have pasted some code to illustrate: import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.InputStream; import java.net.URISyntaxException; import java.net.URL; import java.util.Scanner; /** * * @author parrysg */ public class ResourceTest { public static void main(String[] args) throws URISyntaxException, FileNotFoundException { URL url = ResourceTest.class.getResource("/simpleResource.txt"); FileInputStream fs = new FileInputStream(new File(url.toURI())); Scanner input = new Scanner(fs); System.out.println(input.nextLine()); InputStream is = ResourceTest.class.getResourceAsStream("/simpleResource.txt"); Scanner input2 = new Scanner(fs); System.out.println(input2.nextLine()); } } In the above code, I have used main (i.e. a static member), but if you are opening within a non-static member, it is better to use getClass(): InputStream is = getClass().getResourceAsInputStream(); Note that, if you do just use InputStream, the Exception imports and throws are not needed; it's overall much simpler. regards Stephen Parry On 23 June 2024 15:50:14 BST, Ulf Zibis <ulf.zi...@cosoco.de><mailto:ulf.zi...@cosoco.de> wrote: Hi, I have a resource file im my project under the folder "resources". >From my code, the file is accessed by: FileInputStream rs = new FileInputStream(new File("resources/Palm8BitColors.pal")); This works fine, when I run the application under NetBeans IDE. But the resource file is not included in the JAR file under "dist", so it won't run independently of NetBeans. How is the correct way to integrate and access the file into the JAR? Thanks -Ulf ________________________________ To unsubscribe, e-mail: users-unsubscr...@netbeans.apache.org<mailto:users-unsubscr...@netbeans.apache.org> For additional commands, e-mail: users-h...@netbeans.apache.org<mailto:users-h...@netbeans.apache.org> For further information about the NetBeans mailing lists, visit: https://cwiki.apache.org/confluence/display/NETBEANS/Mailing+lists