Sorry that was just for example #2 :)
> On Apr 27, 2016, at 3:59 PM, Matt Burgess wrote:
>
> If you can represent the expected string format as a regular
> expression, you can use the replaceAll() function [1] with
> back-references:
>
>
If you can represent the expected string format as a regular
expression, you can use the replaceAll() function [1] with
back-references:
${url:replaceAll('(http://[a-zA-Z0-9]+:)[a-zA-Z0-9]+(@.*)','$1x$2')}
original: http://username:p...@host.com
after: http://username:xx...@host.com
Note I