[ CCing a reply to me would be appreciated. Thanks! ]
Hi,
I have a bit of a problem. I've written a portion of a book in emacs,
mostly because it's what I'm most comfortable working in, so I have a
large quantity of ascii text, interspersed with examples - source code
fragments. Emacs wraps lin
uary 16, 2005 12:52 PM
Subject: [users] "fill-paragraph"
> [ CCing a reply to me would be appreciated. Thanks! ]
>
> Hi,
>
> I have a bit of a problem. I've written a portion of a book in emacs,
> mostly because it's what I'm most comfortable working in
On Wed, 16 Feb 2005 14:43:04 -0500, David Teague
<[EMAIL PROTECTED]> wrote:
> David Welton wrote:
>
> > [ need to remove empty paragraphs from portions of code and text]
>
> Daniel suggested
>
> Try the macro from:
> http://www.oooforum.org/forum/viewtopic.phtml?t=6429&highlight=
> It works gre
Hi David,
Very weird. You can search for row breaks (shift-enter), but
you can't replace with them. This is from the regular
expressions help page:
\n
Finds a hard row break that was inserted with Shift+Enter.
To change row breaks into paragraph breaks, enter \n in the
Search for and Replace w
On Thu, 17 Feb 2005 10:40:17 -0500, Anthony Chilco
<[EMAIL PROTECTED]> wrote:
> Hi David,
> Very weird. You can search for row breaks (shift-enter), but
> you can't replace with them. This is from the regular
> expressions help page:
Yeah I had read that, but hoped that there was some way to get a
Looking at the regular expressions, it get stranger and
stranger. Someone else wanted to delete all lines starting
with %. Regular expressions should do it with:
^%*$
^% is a % at the start of a paragraph
* is any number of characters
$ a paragraph break
It doesn't work. If I try just ^%*, only
Hi David,
Brute force method: I recorded a macro to find the next
paragraph mark, then press shift-enter. I assigned it to a
keystroke. Not pretty, but it works. Here's the macro:
sub para2row
rem
--
rem define variables
dim do
On Thu, 17 Feb 2005 11:12:21 -0500, Anthony Chilco
<[EMAIL PROTECTED]> wrote:
> Looking at the regular expressions, it get stranger and
> stranger. Someone else wanted to delete all lines starting
> with %. Regular expressions should do it with:
>
> ^%*$
>
> ^% is a % at the start of a paragraph
I didn't read the help carefully on that one.
%[:alnum:]*$ will do the job to get rid of the lines
starting with %. No help for you, though.
tc
David Welton wrote:
In normal regular expressions, * is any number _of the character it
follows_, so M* would be zero or more consecutive M's, and %* wou
Reply at bottom.
On Fri, 2005-02-18 at 04:40, Anthony Chilco wrote:
> Hi David,
> Very weird. You can search for row breaks (shift-enter), but
> you can't replace with them. This is from the regular
> expressions help page:
>
> \n
> Finds a hard row break that was inserted with Shift+Enter.
>
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