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-Original Message-
From: Nithesh Shetty [mailto:knitheshshe...@yahoo.com]
Sent: Thursday, 24 September 2009 3:27 PM
To: users@qpid.apache.org
Subject: Re: exchangeDeclare funtion hangs
qpidclient test exe built using the below option
g++
qpidclient test exe built using the below option
g++ -pipe -march=pentium4 -mtune=pentium4 -Wconversion -Wpadded -Wall -Wextra
-Wno-shadow -Wpointer -arith -Wcast-qual -Wcast-align -Wno-long-long
-Wvolative-register-var -Winvalid-pch -Wno_system-headers -Woverloaded-virutal
-DNDEBUG -g -L/u
On 09/23/2009 01:48 PM, Nithesh Shetty wrote:
Hi,
Version is qpid0.5
Can you run pstack against both the client and qpidd processes at the
point of the hang?
I have created a class called CMessageQueue
it has two Function called OpenConnection and OpenQueue
member variables are
Session
Hi Rajith,
Thanks for your help. Unfortunately, it helped only partially. With these
properties I'm able to create the producer and the consumer/listener. It
seems, that the consumer/listener needs also access privileges for the
exchange to be able to receive some messages.
But the problem is in
Hi,
Version is qpid0.5
I have created a class called CMessageQueue
it has two Function called OpenConnection and OpenQueue
member variables are
Session m_cSession
Connection m_cConnection.
int CMessageQueue:: OpenConnection(const string szHost,
Hi Nitesh,
What version of Qpid do you see this problem in? Could you post a
small test program that reproduces this?
Thanks,
-Steve
--
Steve Huston, Riverace Corporation
> -Original Message-
> From: Nithesh Shetty [mailto:knitheshshe...@yahoo.com]
> Sent: Wednesday, September 23, 2009
Hi,
When I try to declare exchange using
Session.exchangeDeclare(arg::exchange = "NAME", arg::exclusive = false,
arg::autoDelete = false, arg::type = "direct");
it hangs in
VOID Condition::wait(Mutex& mutex)
{
QPID_POSIX_ASSERT_THROW_IF(pthread_cond_destroy(&condition));
}
Need help
