Dear Members : I tried to compile xyz.jsp from command prompt (using Tomcat 6): jspc -uriroot . xyz.jsp -classpath <jar_file_name> -d <directory_name>; getting errors, but when I simply try:
jspc -uriroot . xyz.jsp it shows no errors, but doesn't produce xyz.java which is expected. Could someone tell me please, the correct command to do this, which will also dump the generated clss file to designated directory and also what's right jar file to compile with - I mean jasper.jar or jsp-api.jar ? Thaks in advance Atanu -- View this message in context: http://www.nabble.com/compiling-jsp-file-from-command-prompt-tp21107639p21107639.html Sent from the Tomcat - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
