Hi,
Yes. This is the correct way.
It is the default in 6.19.0
On Jul 4, 2015 2:51 AM, "Steve Swinsburg" wrote:
> OK solved:
>
> getSecuritySettings().setCryptFactory(new
> KeyInSessionSunJceCryptFactory()); //diff key per user
> final IRequestMapper cryptoMapper = new
> CryptoMapper(getRootReque
This sounds good. I already have a registry where i can register services in a
decoupled way. With spring and @PostConstruct no Problem :-). I would ASK then
every factory if it is responsible for my entity type. But i still see a
problem here. How to prioritize factory if i have more than one f
OK solved:
getSecuritySettings().setCryptFactory(new
KeyInSessionSunJceCryptFactory()); //diff key per user
final IRequestMapper cryptoMapper = new
CryptoMapper(getRootRequestMapper(), this);
setRootRequestMapper(cryptoMapper);
On Fri, Jul 3, 2015 at 9:58 PM, Steve Swinsburg
wrote:
> Hi all,
>
Hi Per,
You can do something like this:
Create a set of compontents that will be your panels to display specific
Persons.
Let's call them PersonPanels.
You can introduce a PersonPanelFactory, which might give you the
appropriate PersonPanel based on the class of the Person (
person.getClass()
@Maxim: Is there anything left to be done within the media components?
Otherwise I am going to vote +1
kind regards
Tobias
> Am 03.07.2015 um 07:43 schrieb Maxim Solodovnik :
>
> OK, will try
> Thanks
>
> On Fri, Jul 3, 2015 at 11:38 AM, Martin Grigorov
> wrote:
>
>> HI Maxim,
>>
>> This w
Hi,
i think about that problem for some time now. Maybe someone alrady has a good
solution.
Let's assume we have a Manager entity and a Tainee entity. Both are Person
entities.
In Model we ask for all persons. So we get a mix from Managers and Trainees in
a list.
Both concrete entity types sh
Hi all,
I am using the cryptomapper to encrypt some URLs and am finding that every
logged in user is getting the same encrypted URL for the same pages.
ie to go to x page is http://url?wicket-crypt=Uqcgp... for both user A and
user B.
Is there any way to make this unique for each user?
In my App
1000 thanks !
François
Le 3 juil. 2015 à 09:47, Sven Meier a écrit :
> Hi,
>
> forms are not allowed to be direct children of :
>
>
>
>
>
>http://stackoverflow.com/questions/5967564/form-inside-a-table
>
> After the first ajax request the browser will re
Hi,
forms are not allowed to be direct children of :
http://stackoverflow.com/questions/5967564/form-inside-a-table
After the first ajax request the browser will reshuffle the dom
elements, so that the form is no longer the parent of the input field: