Johan Compagner wrote:
sharing the same model is also dangerous
What you should do is in the onSubmit of the ajaxbutton in the second page
get the first page (hold on to it somehow that doesn't matter)
and then do
page.getModel().setObject(x)
johan
Thanks. Will give this a go.
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On Tue, Mar 25, 2008 at 3:31 PM, Johan Compagner <[EMAIL PROTECTED]> wrote:
> sharing the same model is also dangerous
>
Right, because of the duplicates you can get when the pages are
serialized and deserialized.
Thanks for pointing that out Johan.
Maurice
---
sharing the same model is also dangerous
What you should do is in the onSubmit of the ajaxbutton in the second page
get the first page (hold on to it somehow that doesn't matter)
and then do
page.getModel().setObject(x)
johan
On Tue, Mar 25, 2008 at 3:26 PM, Maurice Marrink <[EMAIL PROTECTED]
You can not share any component between 2 or more pages if you add a
component to one page it is removed from the other page.
What you should do instead is add a new instance of the component to
each page and let the components share the same model.
If you then update the model and let ajax repaint
Am I even close to doing this correctly?
I have two pages and one panel. A parent page and a popup page. Both
pages contain the Panel. The popup page also contains a Form with an
Ajax button. When I click this button, I want it to update the
TimePanel on both pages.
When the parent launc
