would not have been initialised if written as an inner class when creating
the label.
Please let me know if anyone finds a better way of writing it.
Many thanks again
Vishal
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of writing it.
Many thanks again
Vishal
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Hi all,
For some reason I cannot get the current page number. This is the relevant
part of my code:
PageableListView dataList = new PageableListView(dataList, results, 10) {
protected void populateItem(ListItem item) {
..
}
}
tell me what I have missed?
Regards
Vishal
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Use an dinamic model, ex:
Label currentPage = new Label(currentPage, new
AbstractReadOnlyModelString() {
public String getObject() {
return pagination.getPageable().getCurrentPage();
}
});
On Tue, Nov 9, 2010 at 2:04 PM, Vishal Popat
AjaxPagingNavigator are clicked on.
Any thoughts?
Vishal
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