I forgot to reply to this.
Your observations are absolutely correct.
I realized that I was using the ListView incorrectly, and recreating
it on each refresh.
No wonder I was losing my values. Now it works like a charm.
Thanks.
-Nelson
On Mon, Jun 6, 2011 at 1:29 PM, Pedro Santos wrote:
> Hi Ne
Hi Nelson, ListView recreate its items every render, so it looses
their raw input. You can set reuse items flag - ListView.setReuseItems
and prevent this problem. Also notify the list view about changes in
the list to make it recreate its items by invoking ListView#removeAll
Also you may want to r
I think that my problem is that I am not reusing the models/ recreating
models on refresh. Is that a possible cause?
I have ListView that display the data, and the list itself is dynamic,
depending on what the users selects (that is the reason I need to refresh
the whole form)
I noticed input outs
default processing = false means do not validate, etc. but, inputs are
preserved. make sure your ajaxsubmitlink is inside the correct form.
you can specify one in its constructor.
-igor
On Thu, Jun 2, 2011 at 4:22 PM, Nelson Segura wrote:
> On the AjaxSubmitLink, correct?
> When I do that, the i
Hi Nelson, the raw input has preference and it remains in the form
component until be converted and set in the form component model. For
your use case you can use a simple AjaxLink targeting just the dynamic
fields panel, not the whole form.
On Thu, Jun 2, 2011 at 8:22 PM, Nelson Segura wrote:
>
On the AjaxSubmitLink, correct?
When I do that, the input of the other fields is lost (which has not been
previously submitted).
How does wicket exactly decides whether to show the model value or the user
raw input?
My Ajax links is refreshing the whole panel.
-Nelson
On Thu, Jun 2, 2011 at 4:14
you want setDefaultFormProcessing(false)
-igor
On Thu, Jun 2, 2011 at 3:41 PM, Nelson Segura wrote:
> I have a form to which I need to add dynamic fields using ajax, whenever the
> user clicks on the "add new input" link.
> I need to preserve the current user input, without actually updating the
I have a form to which I need to add dynamic fields using ajax, whenever the
user clicks on the "add new input" link.
I need to preserve the current user input, without actually updating the
backing models (or at least preserve input that is not completely valid, or
do not show errors if the user a
