On Tue, May 23, 2006 at 02:22:32PM +0200, Zdenek Sekera wrote:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]')
do something
endif
2. why when the pattern ends with '+' or '\+' do I get
an error?
Can you be more specific? I tried
:let char = a
:echo char =~
Hi, Benji
On Tue, May 23, 2006 at 02:22:32PM +0200, Zdenek Sekera wrote:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]')
do something
endif
2. why when the pattern ends with '+' or '\+' do I get
an error?
Can you be more specific? I tried
:let
Zdenek Sekera wrote:
Sorry, I should have been clearer:
Note the placement of the '+' in my pattern, somewhere
in the middle, there it doesn't cause any problem:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]'
^
|
-Original Message-
From: Charles E Campbell Jr [mailto:[EMAIL PROTECTED]
Sent: 24 May 2006 15:55
To: Zdenek Sekera
Cc: vim-dev@vim.org
Subject: Re: Pattern questions
Zdenek Sekera wrote:
Sorry, I should have been clearer:
Note the placement of the '+' in my pattern
Zdenek Sekera wrote:
I have this:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]')
do something
endif
Basically it is checking for all non-alphanumeric chars
(expect '=').
1. how do I include the ' char?.
I can't seem to find a proper way.
(I'd like to keep the patter in
-Original Message-
From: A.J.Mechelynck [mailto:[EMAIL PROTECTED]
Sent: 23 May 2006 14:22
To: Zdenek Sekera
Cc: vim-dev@vim.org
Subject: Re: Pattern questions
Zdenek Sekera wrote:
I have this:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]')
do something
endif
On 5/23/06, Zdenek Sekera [EMAIL PROTECTED] wrote:
I have this:
if (char =~ '\m[;|?:[EMAIL PROTECTED]*(){}\\_+-[\]/\]')
do something
endif
Basically it is checking for all non-alphanumeric chars
(expect '=').
1. how do I include the ' char?.
I can't seem to find a proper way.
(I'd
-Original Message-
From: Yakov Lerner [mailto:[EMAIL PROTECTED]
Sent: 23 May 2006 11:37
To: Zdenek Sekera; vim mailing list
Subject: Re: Pattern questions
On 5/23/06, Zdenek Sekera [EMAIL PROTECTED] wrote:
I have this:
if (char =~ '\m[;|?:[EMAIL PROTECTED
