Here is my test data
Example 1 Of medium length Enough words in description
to need one reformat
Example 2 Very short one Needs no reformat
Example 3 Extremely long one This description is long
enough and drivels on and on pointlessly for no other purpose
than to trigger multiple reformatted lines.
Here are the :s commands which produced the best results so far and
show exactly what I'm trying to achieve
:'a,'b-1s/.\{66,}/\=substitute(submatch(0),'\(.\{35}\)\(.\{,30}\)
\(\(.\{,30}\)[ \n]\)\+','\1\2\r@@\1\3','')/g
:'a,'b-1s/^@@\(.\{35}\)/\=substitute(submatch(1),'.',' ','g')
Here is what they do to my test data
Example 1 Of medium length Enough words in description to
need one reformat
Example 2 Very short one Needs no reformat
Example 3 Extremely long one This description is long
multiple reformatted lines.
So, it loses the interior lines of a multiple reformat. To get
those I revisualized the structure of these lines thus:
\(.\{35}\)\(.\{,30}\)\( .\{,30}\)\+
and that all I really needed to do is replace that leading
space in each of the repeated third fields with \r@@\1, ie
that my first :s should be something like
:'a,'b-1s/.\{66,}/\=substitute(submatch(0),'\(.\{35}\)\(.\{,30}\)\(
.\{,30}\)\+', "\=substitute(submatch(3), '^ ', '\r@@\1', '')", 'g')
which produced this output
=substitute(submatch(3), '^ ', '
@@ ', '')
Example 2 Very short one Needs no reformat
=substitute(submatch(3), '^ ', '
@@ ', '')=substitute(submatch(3), '^ ', '
@@ ', '')
which I read as the second \=expression is not being treated
as such, but no variations like doubling the \ to cater for
the enclosing "s makes any difference. Advice as to how to
proceed, please.
--
Graham Lawrence
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