Help please! Im trying to access my web2py server on a Rpi from another 
device to run an application that is on the server. From local host it runs 
and executes fine, no problem, but i just cant connect to it from other 
devices. 
I do what is said in this message and I get the following error: 

*ERROR:Rocker.Errors.Port80:Socket 192.168.1.172:80 in use by other process 
and it wont share.*

What am I doing wrong? How can i get around this? 
 Please help!!

On Sunday, December 9, 2012 at 5:42:58 AM UTC-5, Richard Shea wrote:
>
> Thank you Massimo.
>
> On Saturday, December 8, 2012 5:52:28 AM UTC+13, Massimo Di Pierro wrote:
>>
>> python web2py.py -a passwd -i 0.0.0.0 -p 80
>>
>> On Friday, 7 December 2012 03:21:55 UTC-6, Richard Shea wrote:
>>>
>>> I want to start a web2py server so that it can be accessed externally
>>> to the hosting server.
>>>
>>> I've read this http://web2py.com/books/default/chapter/29/03
>>>
>>> By default, web2py runs its web server on 127.0.0.1:8000 (port 8000
>>>> on localhost), but you can run it on any available IP address and
>>>> port. You can query the IP address of your network interface by
>>>> opening a command line and typing ipconfig on Windows or ifconfig on
>>>> OS X and Linux. From now on we assume web2py is running on localhost
>>>> (127.0.0.1:8000). Use 0.0.0.0:80 to run web2py publicly on any of your
>>>> network interfaces.
>>>>
>>>
>>> but I can't find how to "Use 0.0.0.0:80" ?
>>>
>>> There doesn't seem to be a command line argument which does that ? 
>>>
>>> I'm aware of the command line arg to change the port but how do I allow 
>>> access from all addresses.
>>>
>>> thanks
>>>
>>> Richard.
>>>
>>>

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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