I have a model that has: db.Field('screenshot', 'upload'))
In my controller i have: def add(): form = SQLFORM(db.apps) if form.accepts(request.vars, session): redirect(URL(r=request, c='default', f='index')) return dict(form = form) and in my view I have: {{for app in records:}} <div> <img src="{{=URL(r=request, c='uploads', f=app.screenshot)}}"> {{=A(app.name, _href=URL(r=request, f=app.link))}} <span>by {{=app.author}}</span> <br/> <span>{{=app.description}}</span> </div> {{pass}} this returns a broken image. anyone know how to display an image from the upload of a form? --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---