Hi, I've been trying to upload a file via a webservice, without any success. I'm exposing a serv_upload() action via @service.run. How can I get a handle of the file in the serv_upload() action?
I'm using (trying) to use urllib2 to get the file from the server. I've googled but haven't seem to manage to find anything usable out-of-the box. Any pointers on this? Should I develop my own, is there an alternative to urllib + urllib2 on the client, ... By the way the consumer will be a desktop app. txs, Miguel -- You received this message because you are subscribed to the Google Groups "web2py-users" group. To post to this group, send email to web...@googlegroups.com. To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/web2py?hl=en.
