On Sunday, December 4, 2016 at 11:43:40 AM UTC-5, Marlysson Silva wrote:
>
> Then isn't online/offline it verify whether user get out focus on current
> page..
>
In that context, "offline" means that the browser no longer has an internet
connection.
>
> Em sábado, 3 de dezembro de 2016
Then isn't online/offline it verify whether user get out focus on current
page..
Em sábado, 3 de dezembro de 2016 17:36:10 UTC-3, Anthony escreveu:
>
> On Saturday, December 3, 2016 at 2:25:50 PM UTC-5, Marlysson Silva wrote:
>>
>> You can do it with javascript, using:
>>
>> Api navigador:
>>
>>
On Saturday, December 3, 2016 at 2:25:50 PM UTC-5, Marlysson Silva wrote:
>
> You can do it with javascript, using:
>
> Api navigador:
> https://developer.mozilla.org/en-US/docs/Online_and_offline_events#Overview
>
> https://developer.mozilla.org/en-US/docs/Online_and_offline_events#Overview
>
You can do it with javascript, using:
Api navigador:
https://developer.mozilla.org/en-US/docs/Online_and_offline_events#Overview
https://developer.mozilla.org/en-US/docs/Online_and_offline_events#Overview
Em sexta-feira, 2 de dezembro de 2016 15:11:08 UTC-3, Ramos escreveu:
>
> What could be the
You need a websocket server like
web2py/gluon/contrib/websocket_messaging.py Examples are i the file itself.
On Friday, 2 December 2016 12:11:08 UTC-6, Ramos wrote:
>
> What could be the best way to check if a user is disconnects?
>
> I was thinking of this
>
>
>
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