You could try something like this:
(filename, fullfilename) =
db.tablename.uploadfield.retrieve(record.uploadfield, nameonly=True)
On Wednesday, 29 July 2015 01:05:58 UTC+12, Prasad Muley wrote:
>
> Hi All,
>
> file name gets store as *93f00342868f4085.73716c2e6c6f67.log *in db
> fie
That's the easiest way. If you do want to decode the filename yourself,
note the encoded filename is only the last segment of the new filename
(i.e., the part after the last "." -- in this case, "73716c2e6c6f67").
Anthony
On Tuesday, July 28, 2015 at 4:13:32 PM UTC-4, Limedrop wrote:
>
> You co
On Tuesday, July 28, 2015 at 5:29:28 PM UTC-7, Anthony wrote:
>
> That's the easiest way. If you do want to decode the filename yourself,
> note the encoded filename is only the last segment of the new filename
> (i.e., the part after the last "." -- in this case, "73716c2e6c6f67").
>
>>
>>>
An
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