First, I'd advise against doing this, at least initially. Take what Web2py 
gives you for free and concentrate on your app.

2nd, web2py URLs do not end in ".html"

3rd, i think you would use this for 
login: 
http://web2py.com/books/default/chapter/29/09/access-control#Manual-Authentication


On Thursday, June 15, 2017 at 12:42:22 AM UTC-7, hardclock wrote:
>
>
> I made a custom signin form using javascript and ajax to check for 
> duplicated user/wrong username-password combination.The ajax request I made 
> is like this
>
> $.ajax({
> url:'../default/signin.html',
> type:'POST',
> data:{
>    username:username,
>    password:password,
>    email:email
>     },
> success:function (errorCode) {   //recieve the error code from default.py     
>    if( errorCode ==0){      //print error message,stop the submit page
>    }else{ //redirect to user's page
>     }
> });
> The ajax sends request to the same page,then the deafult/(signin)function 
> will check database for match usn/pssw and return back the error code.
> That was my original approach but I couldn't return back the value to the 
> ajax request.Is there anyway to do it?
> Please excuse the weird text formatting,I copied them directly from the 
> development console.
>
>

-- 
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
--- 
You received this message because you are subscribed to the Google Groups 
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to web2py+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.

Reply via email to