hi, anthony, thank you so much for your kind attention, problem solved now
def __add_2(table):
form = crud.create(table,
next = URL(request.application,
request.controller,
index_link),
On Friday, April 22, 2011 2:46:44 AM UTC-4, 黄祥 wrote:
>
> thank you so much for your pointer, bruno, it seems onaccept, can't receive
> request.vars that been passed during form submit, because when i tried to
> replace the request.vars into the value id (1, 2, etc), no errors occured.
> did an
thank you so much for your pointer, bruno, it seems onaccept, can't receive
request.vars that been passed during form submit, because when i tried to
replace the request.vars into the value id (1, 2, etc), no errors occured.
did anyone have meet the same problem?
thank you very much before
On Fri
You can try to set default before the creation of the form, something like:
db.booking.status.default="Booked"
form = crud.create(db.booking)
--
Bruno Rocha
[ About me: http://zerp.ly/rochacbruno ]
On Fri, Apr 22, 2011 at 2:24 AM, Stifan Kristi wrote:
> a, i c, thank you so much for your poi
a, i c, thank you so much for your pointer anthony, is there any others way
to that without using update() or update_record()?
thank you very much
On Fri, Apr 22, 2011 at 1:33 AM, Anthony wrote:
> I think onaccept has to be a function.
>
> On Thursday, April 21, 2011 1:12:24 PM UTC-4, 黄祥 wrote:
I think onaccept has to be a function.
On Thursday, April 21, 2011 1:12:24 PM UTC-4, 黄祥 wrote:
> hi,
>
> is it possible to create new record and update status simultaneously?
> e.g. update()
> def __add_2():
> form = crud.create(db.booking, next = URL(request.application,
> request.contr
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