[web2py] Re: scheduled task ignoring period

2017-04-26 Thread Anthony
Do you have more than one of the same task getting scheduled? Where is this line: myScheduler.queue_task('myfunc', repeats=0, period=86400, timeout=1200, prevent_drift=True, immediate=True) If it is in a model file, every time the model file is accessed (including whenever a scheduler task is

[web2py] Re: scheduled task ignoring period

2017-04-26 Thread James Holstead
Status is COMPLETED in the scheduler_run table, run time of about 5 seconds. Checking the scheduler_task table I'm noticing the next_run_time is 1 day ahead. period is 86400, repeats is 0, times_run is 1 Thanks for the help! > The next check is the entries in the "scheduler_run" table, which

[web2py] Re: scheduled task ignoring period

2017-04-26 Thread Dave S
On Wednesday, April 26, 2017 at 6:09:30 AM UTC-7, James Holstead wrote: > > I've tried returning 0,1,2,None. It behaves the same regardless. There is > only one user in my development database: > > DEBUG:web2py.app.myapp:Found user: 123456789 > > DEBUG:web2py.app.myapp:Updated. > > DEBUG:web

[web2py] Re: scheduled task ignoring period

2017-04-26 Thread James Holstead
I've tried returning 0,1,2,None. It behaves the same regardless. There is only one user in my development database: DEBUG:web2py.app.myapp:Found user: 123456789 DEBUG:web2py.app.myapp:Updated. DEBUG:web2py.app.myapp:new task report: COMPLETED DEBUG:web2py.app.myapp: result: 1 DEBUG:

[web2py] Re: scheduled task ignoring period

2017-04-25 Thread Dave S
On Tuesday, April 25, 2017 at 9:34:48 AM UTC-7, James Holstead wrote: > > I have a scheduler.py in my models directory with two functions, > syncUsers, testAdd > > # create scheduler > myScheduler = Scheduler(db, migrate=False, tasks=dict(myfunc=syncUsers)) > > #myScheduler = Scheduler(db,