Friends,
I have an external method that returns a string containing dtml, but
I want it to evaluate the dtml and return the result. How do I do
that?
I noticed in, say,
/usr/share/zope/lib/python/Products/ExternalMethod/ExternalMethod.py,
that dtml-containing *files* are used as object
dtml-foo.[bar.dot].y
In all the computer languages I know there's already a convention for
solving this kind of problem.
dtml-foo.bar\.dot.y
But I prefer path-style identifiers:
dtml-/foo/bar\.dot/y
Then the correspondence to the site's folder structure is evident.
Plus you
Is there a way to get the current object's class name?
dtml-var "this.__class__.__name__"
doesn't work.
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