On May 20, 1:06 pm, Eric <[email protected]> wrote:
> :lower[ :l_name ] works just right.
>
> Thanks, one less nit off my checklist.
Note that that doesn't work in Ruby 1.9, since ruby defines Symbol#
[]. Here's a better way:
Emp.select(:id, (:f_name.sql_string + :l_name).as(:name)).
order{[lower(l_name), lower(f_name)]}.all
You need to be using Sequel 3.0 for that code to work.
Jeremy
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