Hi Ajay,
Here's some code; change as required, I grab the folder to drop the
attachments into from the config file using getInitParameter() in the init
method.
public void service(Mail mail) throws MessagingException
{
try
{
MimeMessage msg = (MimeMessage) mail.getMessage();
Multipart mp = (Multipart) msg.getContent();
for (int j = 0, n = mp.getCount(); j < n; j++)
{
Part part = mp.getBodyPart(j);
if(part.getFileName()==null)
continue;
//log("Content Type = " + part.getContentType()+ "
Disposition = " + part.getDisposition()+ " Filename: = " +
part.getFileName());
File outputFile = new File(folderPath+part.getFileName());
FileOutputStream outputStream = new
FileOutputStream(outputFile);
InputStream inputStream = part.getInputStream();
int i;
while((i = inputStream.read()) != -1)
outputStream.write(i);
outputStream.close();
}
Carl
-----Original Message-----
From: Ajay Chitre [mailto:[EMAIL PROTECTED]
Sent: Wednesday, July 09, 2008 3:37 AM
To: James Users List
Subject: Processing Email Attachments...
When an email comes in to my James server with one ore more attachments, I
need to get the attached files and save them someplace. Can someone
(please, please) provide a code snippet of processing email attachments
under James?
I know I can get the file name as follows:
try {
if (mail.getMessage().getContent() instanceof MimeMultipart) {
MimeMultipart mmp = (MimeMultipart) mail.getMessage().getContent();
for (int i = 0; i < mmp.getCount(); i++) {
MimeBodyPart mbp = (MimeBodyPart) mmp.getBodyPart(i);
System.out.println("File name: " + mbp.getFileName());
}
}
} catch ( Exception e ) {
System.out.println("Error: " + e.getMessage());
}
Do I need to write code to explicitly read the file using InputStream? Is
there a better way to do this? Any help in this regard will be greatly
appreciated. Thanks.
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