Java uses Pass by Reference for Object's, and Pass by Value for intrinsic
types.
(*Chris*)
----- Original Message -----
From: Shiraz Wasim Zaidi <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, August 12, 1999 7:06 PM
Subject: Re: will this code work?
> Hi!,
>
> No, It wont work....
>
> The result will be null . Method parameters variables are created
> when a method is invoked and its value is initialized with the method
> argument.
> i.e copy of actual argument is passed not the actual argument.
>
> Shiraz
>
> -----Original Message-----
> From: Chris Pratt <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
> Date: Thursday, August 12, 1999 7:32 PM
> Subject: Re: will this code work?
>
>
> >Yes it will. But that is an awefully convoluted way of doing
> >out.println("my name"); At this point I would suggest you read through
the
> >Java Tutorial on Sun's site, it's free and it will teach you these
> >rudimentary things.
> > (*Chris*)
> >
> >----- Original Message -----
> >From: Duke Martin <[EMAIL PROTECTED]>
> >To: <[EMAIL PROTECTED]>
> >Sent: Thursday, August 12, 1999 4:57 PM
> >Subject: will this code work?
> >
> >
> >> String temp = null;
> >> temp = process_me(temp);
> >>
> >> out.println(temp);
> >>
> >> public String process_me(String temp)
> >> {
> >> temp = "my name";
> >> return temp;
> >> }
> >>
> >> I would like to this the output of this servlet to print "my name" to
the
> >> screen. Will this work?
> >>
> >> thanks
> >>
> >>
>
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> >
>
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>
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