wow ... long way of saying ..
Yes it works, but depending on what you think the author is asking, not as
he expects.
But I do like the clarity!!!!
Thor HW
----- Original Message -----
From: Ted Neward <[EMAIL PROTECTED]>
To: Thor Heinrichs-Wolpert <[EMAIL PROTECTED]>;
<[EMAIL PROTECTED]>
Sent: Thursday, August 12, 1999 10:57 PM
Subject: Re: Re: will this code work?
> Folks, the confusion, IMHO, is pretty simple: the difference between
> returning a parameter and the parameter passed in to the method.
>
> For example, had the code been written this way:
>
> public class Param
> {
> public static void main(String[] args)
> {
> String temp = null;
> manipParameter(temp);
> System.out.println("temp = " + temp);
> }
>
> private static void manipParameter(String param)
> {
> param = "This should be modified";
> }
> }
>
> the resulting output would be:
>
> temp = null
>
> because Java supports pass-by-value semantics, not pass-by-reference, even
> for Object-derived types. (This is where Java's insistence that it has no
> pointers really trips people up.) This means that the POINTER to String,
> held by temp, is copied into the String reference named "param", and
> subsequent modification of "param" has no effect on the original reference
> "temp".
>
> For all you C++-heads out there, the difference is one of
>
> void manipParameter(String* pString); // THIS is what Java does,
effectively
>
> vs.
>
> void manipParameter(String& pString); // THIS is NOT what Java does
>
> Hence, Shiraz is correct in that the *parameter*, temp, (not the lvalue of
> the return value's assignment) will not be modified.
>
> However, because the original code was written to not only use the
(wrongly)
> assumed pass-by-reference semantics, but also to copy the return value
into
> temp:
>
> >> >> temp = process_me(temp);
>
> the code worked as expected.
>
> In short, everybody's right, bur for different reasons. :)
>
> Ted Neward
> Patterns/C++/Java/CORBA/EJB/COM-DCOM spoken here
> http://www.javageeks.com/~tneward
> "I don't even speak for myself; my wife won't let me." --Me
>
> -----Original Message-----
> From: Thor Heinrichs-Wolpert <[EMAIL PROTECTED]>
> To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
> Date: Tuesday, August 10, 1999 7:04 PM
> Subject: Re: will this code work?
>
>
> >ummm ... you're wrong here.
> >Yes it will work, as Chris said it would.
> >
> >It follows the basic right hand operation rules, and does indeed printout
> >"my name".
> >
> >I do think it is convoluted and is not clear as to what is being
attempted.
> >The function is returning "my name", it is not over-writing the variable
> >passed in.
> >
> >Passing in "temp" to the function does nothing, but then, it isn't being
> >used to do anything inside of the function.
> >
> >Thor HW
> >----- Original Message -----
> >From: Shiraz Wasim Zaidi <[EMAIL PROTECTED]>
> >To: <[EMAIL PROTECTED]>
> >Sent: Thursday, August 12, 1999 7:06 PM
> >Subject: Re: will this code work?
> >
> >
> >> Hi!,
> >>
> >> No, It wont work....
> >>
> >> The result will be null . Method parameters variables are created
> >> when a method is invoked and its value is initialized with the method
> >> argument.
> >> i.e copy of actual argument is passed not the actual argument.
> >>
> >> Shiraz
> >>
> >> -----Original Message-----
> >> From: Chris Pratt <[EMAIL PROTECTED]>
> >> To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
> >> Date: Thursday, August 12, 1999 7:32 PM
> >> Subject: Re: will this code work?
> >>
> >>
> >> >Yes it will. But that is an awefully convoluted way of doing
> >> >out.println("my name"); At this point I would suggest you read
through
> >the
> >> >Java Tutorial on Sun's site, it's free and it will teach you these
> >> >rudimentary things.
> >> > (*Chris*)
> >> >
> >> >----- Original Message -----
> >> >From: Duke Martin <[EMAIL PROTECTED]>
> >> >To: <[EMAIL PROTECTED]>
> >> >Sent: Thursday, August 12, 1999 4:57 PM
> >> >Subject: will this code work?
> >> >
> >> >
> >> >> String temp = null;
> >> >> temp = process_me(temp);
> >> >>
> >> >> out.println(temp);
> >> >>
> >> >> public String process_me(String temp)
> >> >> {
> >> >> temp = "my name";
> >> >> return temp;
> >> >> }
> >> >>
> >> >> I would like to this the output of this servlet to print "my name"
to
> >the
> >> >> screen. Will this work?
> >> >>
> >> >> thanks
> >> >>
> >> >>
> >>
>
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> >> >
> >>
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