Hi! I am manually installing a web application. It requires the url of a
servlet as
http://mycomp/servlet/com.abc.servlet.login
My servlet directory is /export/home/servlets/. In the instruction, I
need to put login.class (the servlet class) under
/export/home/servlets/com/abc/servlet/
And I've configured JRun's servlet directory as /export/home/servlets/
and /export/home/servlets/com/abc/servlet/
But the JRun still cannot find com.abc.servlet.login. Can anyone help? I
really feel the form of http://mycomp/servlet/com.abc.servlet.login is
wired.
Thank you!
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Xizhen
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