Do you now the way I can put a value in the <INPUT type="file"...> field?
> Hi,
> first of all you should use ENCTYPE="multipart/form-data" METHOD="post" in
> your FORM. If you have the following form:
>
> <FORM action="http://server.com/cgi/handle"
> enctype="multipart/form-data"
> method="post">
> <P>
> What is your name? <INPUT type="text" name="submit-name"><BR>
> What files are you sending? <INPUT type="file" name="files"><BR>
> <INPUT type="submit" value="Send"> <INPUT type="reset">
> </FORM>
>
> and you type Larry and choose file1.txt your user agent will send back to
> the server the followings:
>
> Content-Type: multipart/form-data; boundary=AaB03x
>
> --AaB03x
> Content-Disposition: form-data; name="submit-name"
>
> Larry
> --AaB03x
> Content-Disposition: form-data; name="files"; filename="file1.txt"
> Content-Type: text/plain
>
> ... contents of file1.txt ...
> --AaB03x--
>
> So you have to:
> -use getHeader("Content-type") with somme processing to retrieve the
> boundary(AaB03x in our case)
> -use getInputStream() to obtain the stream containing de request data.
> -retrieve the content of the file from the stream using boundary value.
>
> Maybe you don't have to work so hard if your server has already somme
> classes for doing all this stuff.
>
> Bye
>
> -----Original Message-----
> From: A mailing list for discussion about Sun Microsystem's Java Servlet
> API Technology. [mailto:[EMAIL PROTECTED]]On Behalf Of
> Sushant Kumar
> Sent: Monday, August 21, 2000 4:46 PM
> To: [EMAIL PROTECTED]
> Subject: File upload..
>
>
> Hi all..
>
> I am trying to upload a file to my server using Form. I am setting one of
> the the input's type as File. But, on the servlet side I couldn't find any
> method to read the request's data as file..
> does anyone has any idea about how to do this?? I am using web-server
> provided with jswdk1.0.1.
>
> Regards,
> Sushant
>
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--
Guillaume ORIOL
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