I tried to do something like this earlier and it turned out that I needed
to put the xml files into tomcat_home/bin
I didn't really find out if this is configurable but it seemed to work for
me. I am sure that if you look into this it might be possible to change
where the XML and other related files should go.
Not an ideal solution, but I hope this helps somewhat.
Dominic
At 08:11 AM 1/8/01 -1000, you wrote:
>Hi,
>
>I have a servlet (code is attached) to convert a xml file to html on server
>side. The servlet, XSLServlet.class, is run on Tomcat3.1/WINDOWS 98 at
>directory C:\jakarta-tomcat\webapps\ROOT\WEB-INF\classes. The two input
>source files, normal.xml and normal.xsl are located at the same directory as
>XSLServlet.class is. However, when I involk XSLServlet
>(http://localhost/XSLServlet) I got following message:
>
>Error: 500
>
>Location: /servlet/XSLServlet
>
>Internal Servlet Error:
>
>java.io.FileNotFoundException: normal.xsl (The system cannot find the file
>specified)
> at java.io.FileInputStream.open(Native Method)
> at java.io.FileInputStream.(FileInputStream.java:64)
> at java.io.FileReader.(FileReader.java:38)
> at XSLServlet.doPost(XSLServlet.java:25)
> at XSLServlet.doGet(XSLServlet.java:19)
> at javax.servlet.http.HttpServlet.service(HttpServlet.java:740)
> at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
> at
>org.apache.tomcat.core.ServletWrapper.handleRequest(ServletWrapper.java:503)
> at
>org.apache.tomcat.core.ServletWrapper.handleRequest(ServletWrapper.java:597)
> at
>org.apache.tomcat.servlets.InvokerServlet.service(InvokerServlet.java:257)
> at javax.servlet.http.HttpServlet.service(HttpServlet.java:853)
> at
>org.apache.tomcat.core.ServletWrapper.handleRequest(ServletWrapper.java:503)
> at
>org.apache.tomcat.core.ContextManager.service(ContextManager.java:559)
> at
>org.apache.tomcat.service.http.HttpConnectionHandler.processConnection(HttpConnectionHandler.java:160)
> at
>org.apache.tomcat.service.TcpConnectionThread.run(SimpleTcpEndpoint.java:338)
> at java.lang.Thread.run(Thread.java:484)
>==============================================================
>
>Could any one tell me why this happens?
>
>Thanks you in advance.
>
>Peter
>
>
>P.S. Source code:
>===============================================================
>
>import javax.servlet.*;
>import javax.servlet.http.*;
>import java.io.*;
>import java.util.*;
>
>import com.lotus.xsl.XSLTInputSource;
>import com.lotus.xsl.XSLTResultTarget;
>import com.lotus.xsl.XSLProcessor;
>import org.xml.sax.SAXException;
>
>
>public class XSLServlet extends HttpServlet {
>
> public void init(ServletConfig config) throws ServletException {
> super.init(config);
> }
>
> public void doGet(HttpServletRequest request, HttpServletResponse
>response) throws ServletException, IOException {
> doPost(request, response);
> }
>
> //Process the HTTP Post request
> public void doPost(HttpServletRequest request, HttpServletResponse
>response) throws ServletException, IOException {
> PrintWriter out = new PrintWriter (response.getOutputStream());
> FileReader xslReader = new FileReader("normal.xsl");
> FileReader xmlReader = new FileReader("normal.xml");
>
> response.setContentType("text/html");
> try
> {
> XSLProcessor proc = new XSLProcessor();
> //proc.setStylesheetParam("invoiceNum", invoiceNum);
> proc.process(new XSLTInputSource(xmlReader),new
>XSLTInputSource(xslReader),new XSLTResultTarget(out));
> }
> catch (SAXException saxE)
> {
> out.write(saxE.getMessage());
> saxE.printStackTrace(out);
> }
>
> out.close();
> }
>
> //Get Servlet information
> public String getServletInfo() {
> return "XSLServlet Information";
> }
>}
>
>
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-------------------------------------------
Dominic O'Reirdan
Access Technology Group
Internet Engineering
Cable & Wireless USA
703-292-2815
-------------------------------------------
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