The servlet specification does not require that the RequestDispatcher.forward() method
be able to forward request objects between two
distinct instances of a servlet container. If a vendor chooses, each instance of the
container may be contained within distinct JVMs. If
this is the case, then there is little chance that a ServletContext in on JVM has any
clue as to the existence of another ServletContext in
a different JVM.
If you use the response.sendRedirect() method, you will keep all of your parameters
because you have to specify them in the url:
http://server2.myHost.org/myAppOnServer2/Foo?p1=1&p2=2.........
The browser will make a request to the URL specified in the HTTP response (status
303??? or is it 302??).
Bo Xu wrote:
> Bartsch Axel wrote:
>
> > Exactly.
> >
> > Thats why I would prefer to use solution 2:
> > within servlet1:
> > instead of forwarding the request (using the RequestDispatcher) send a response
>using response.sendRedirect(String <url of servlet2>).
> > Then the browser will resend its request to the correct URL of servlet2
> >
> > Will the same parameters included in the browsers original request be resend also
>in the browsers 'redirect' request?
> >
> > Axel Lannion/France
> > [...]
>
> Hi :-) I am not sure, from several emails and my work, I think the
> original parameters:
>
> - will be lost after sendRedirect(...)
> - will be "remembered :-)" after RequestDispatcher
>
> if it is wrong, please correct it, thanks :-)
>
> Bo
> May.18, 2001
>
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