hi! i could think of two ways: 1. use "hidden fields" to set a field indicating that the user already had a session. 2. use "url rewriting" in your app: if you get a request with an invalid(ed) session id, you know the session timed out.
can anybody please clarify this: if a session timed out, the client doesn't know anything about this, so it should send the session with the following request, right? -mw At 11:53 07.03.2002 -0500, you wrote: >I have a web application which uses container managed authentication. > >When a user is logged into the application and the session times out, the >next user-initiated action will result in the login page being displayed >(the j2ee container makes this happen). > >How is it possible to tell that the reason that the user was directed to the >login page was because the session timed out and not because it was the >users first attempt at accessing the resource? > >I would like to display message to the user indicating that the reason they >are in the login page is the result of a session timeout. > >I am currently constrained to use of the Servlet 2.2/JSP 1.1 spec. > >TIA, >Michelle > >___________________________________________________________________________ >To unsubscribe, send email to [EMAIL PROTECTED] and include in the body >of the message "signoff SERVLET-INTEREST". > >Archives: http://archives.java.sun.com/archives/servlet-interest.html >Resources: http://java.sun.com/products/servlet/external-resources.html >LISTSERV Help: http://www.lsoft.com/manuals/user/user.html ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html
