Wilson,
This is very difficult to do. It is funny that the html is so
easy, but actually retrieving the file is so difficult. First, the form
must be a multipart form like this:
<form method="POST" enctype="multipart/form-data"
action="yourfile.html">
I'm afraid I do not know JSP, but only use servlets. For a Servlet
request, I use Jason Hunter's MultipartParser class at
www.servlets.com/cos/javadoc/com/oreilly/servlet/multipart/MultipartPars
er.html
Then, after declaring the MultipartRequest like this:
Multi = new MultipartRequest(req, Directory, maxsize, filename,
OverwriteType);
You have to parse through the parameter names:
Enumeration params = multi.getParameterNames();
<go through enumeration here in a while loop and set your parameters>
Then, get the file names:
Enumeration files = multi.getFileNames();
Then, finally get your file(s):
While (files.hasMoreElements()) {
String name = (String)files.nextElement();
String filename = multi.getFilesystemName(name);
String type = multi.getContentType(name);
File f = multi.getFile(name);
Vars.put(String.valueOf(i),filename);
}
Not easy, huh?
- Chuck
-----Original Message-----
From: A mailing list for discussion about Sun Microsystem's Java Servlet
API Technology. [mailto:[EMAIL PROTECTED]] On Behalf Of
Wilson Edgar
Sent: Tuesday, March 19, 2002 5:51 AM
To: [EMAIL PROTECTED]
Subject: file upload
hi there good people
i have a <form> in my jsp and one of the field is a
<input type=file ....>
to allow the client to brownse through his file system.
My question is quite simple, how can i capture the choosen file and copy
to
a directory in the server.
a practical example would be very much appreciated
thanks in advance for your time
wilson edgar
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