You need to specify the full name of the class (ex.
com.fjklas.GetUserIdentity)

Edward wrote:

> I have a question about servlet's web.xml file,I put my files into follows 
>directories:
>D:\Apache Tomcat 4.0\webapps\login\WEB-INF\classes\GetUserIdentity.class
>D:\Apache Tomcat 4.0\webapps\login\WEB-INF\web.xml
>D:\Apache Tomcat 4.0\webapps\login\servlets\index.html
>
>My web.xml is follows:
>
><?xml version="1.0" encoding="UTF-8"?>
><!DOCTYPE web-app
>    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
>    "http://java.sun.com/j2ee/dtds/web-app_2_2.dtd";>
><web-app>
>    <session-config>
>     <session-timeout>
>        30
>     </session-timeout>
>    </session-config>
>    <welcome-file-list>
>     <welcome-file>
>        index.html
>     </welcome-file>
>    </welcome-file-list>
>    <servlet>
>        <servlet-name>
>           GetUserIdentity
>        </servlet-name>
>        <servlet-class>
>           GetUserIdentity
>        </servlet-class>
>    </servlet>
></web-app>        //---------Here is 24 line---------
>
>When I start Tomcat4.0,I got error:
>
>Starting service Tomcat-Standalone
>Apache Tomcat/4.0.1
>PARSE error at line 24 column 12
>org.xml.sax.SAXParseException: The content of element type "web-app" must match
>"(icon?,display-name?,description?,distributable?,context-param*,filter*,filter-
>mapping*,listener*,servlet*,servlet-mapping*,session-config?,mime-mapping*,welco
>me-file-list?,error-page*,taglib*,resource-env-ref*,resource-ref*,security-const
>raint*,login-config?,security-role*,env-entry*,ejb-ref*,ejb-local-ref*)".
>Starting service Tomcat-Apache
>Apache Tomcat/4.0.1
>
>I don't know why my web.xml is error,how to correct it?
>Thanks!
>Edward
>
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