I have a servlet file,like follows:

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.*;
public class a1 extends HttpServlet{
    public void doGet(HttpServletResponse req,HttpServletResponse resp) throws ServletException,IOException{
        PrintWriter pw=resp.getWriter();
        pw.println("<html><body>Hello World!</body></html>");
        pw.close();
    }
}

and web.xml is follows:
<?xml version="1.0" encoding="ISO-8859-1"?>

<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "
http://java.sun.com/dtd/web-app_2_3.dtd">

<web-app>
   <servlet>
   <servlet-name>a1</servlet-name>
   <servlet-class>a1</servlet-class>
   </servlet>
</web-app>

I use Tomcat5.0,I don't want to use Tomcat5 default path ,so I put a1.class into \Tomcat 5.0\webapps\test\WEB-INF\classes,and I have added a sentence into server.xml,like follows:

<Context path="test" docBase="test" debug="0"/>

but when I run it in IE6,like follows:
http://localhost:8080/test/servlets/a1

it raises HTTP Status 404 error,"The requested resource (/test/servlets/a1) is not available."

Why? I have configure path! Please help.
Thanks in advance
Edward

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