Hi, A servlet won't work automatically in this way with the standard install of Tomcat.
You will need to do one of the following: a) in conf/web.xml, enable the InvokerServlet entry by uncommenting in b) add the invoker servlet manually to the web.xml file in /rma/WEB-INF c) add a <servlet> and <servlet-mapping> entry in your web.xml file (this is the preferred method). You can check the webapps/servlet-examples/WEB- INF/web.xml file for an example of how to do this. eg, add this to your web.xml <servlet> <servlet-name>Testin</servlet-name> <servlet-class>Testin.class</servlet-class> </servlet> <servlet-mapping> <servlet-name>Testin</servlet-name> <url-pattern>/servlet/Testin</url-pattern> </servlet-mapping> The first part, says that the "Testin" servlet class is "Testin.class". The second part says that when you access /servlet/Testin, under your web app /rma, then it should use the Testin servlet. Hope that helps, Neale Rudd metawerx java hosting http://www.metawerx.net ___________________________________________________________________________ To unsubscribe, send email to [EMAIL PROTECTED] and include in the body of the message "signoff SERVLET-INTEREST". Archives: http://archives.java.sun.com/archives/servlet-interest.html Resources: http://java.sun.com/products/servlet/external-resources.html LISTSERV Help: http://www.lsoft.com/manuals/user/user.html